R5F121BCAFP datasheet(53/85 Pages) RENESAS

53 / 85 page

RL78/G16

3. ELECTRICAL SPECIFICATIONS (TA

= −40 to +105°C, TA = −40 to +125°C)

R01DS0431EJ0130

Rev.1.30

Page 53 of 85

May 19, 2025

3.3

DC Characteristics

3.3.1

Pin characteristics

[TA =

−40 to +105°C: G products, TA = −40 to +125°C: M products, 2.4 V ≤ VDD ≤ 5.5 V, VSS = 0 V]

(1/2)

Item

Symbol

Condition

MIN.

TYP.

MAX.

Unit

Output current,

highNote 1

IOH1

Per pin for P00 to P07, P10 to P17, P20 to P23, P40 to P43, P121,

P122, P125

−3.0Note 2

Total of P06, P07, P20 to

P23, P40 to P43, P121, P122,

P125

(when duty ≤ 70%Note 3)

4.0 V

≤ V

≤ 5.5 V

−25.0

2.4 V

≤ V

DD < 4.0 V

−7.0

Total of P00 to P05, P10 to

P17

(when duty ≤ 70%Note 3)

4.0 V

≤ V

≤ 5.5 V

−24.0

2.4 V

≤ V

DD < 4.0 V

−6.0

Total of all pins

(when duty ≤ 70%Note 3)

−40.0

Output current,

low Note 4

IOL1

Per pin for P00 to P07, P10 to P17, P20 to P23, P40 to P43, P121,

P122, P125

8.5Note 2

Per pin for P60, P61

15.0Note 2

Total of P06, P07, P20 to

P23, P40 to P43, P121, P122,

P125

(when duty ≤ 70%Note 3)

4.0 V

≤ V

≤ 5.5 V

= −40 to +105°C

50.0Note 5

= −40 to +125°C

40.0

2.7 V

≤ V

DD < 4.0 V

10.5

2.4 V

≤ V

DD < 2.7 V

4.2

Total of P00 to P05, P10 to

P17, P60, P61

(when duty ≤ 70%Note 3)

4.0 V

≤ V

≤ 5.5 V

= −40 to +105°C

50.0Note 5

= −40 to +125°C

40.0

2.7 V

≤ V

DD < 4.0 V

9.0

2.4 V

≤ V

DD < 2.7 V

3.6

Total of all pins

(when duty ≤ 70%Note 3)

= −40 to +105°C

80.0

= −40 to +125°C

60.0

Note 1.

Device operation is guaranteed at the listed currents even if current is flowing from the VDD pin to an output

pin.

Note 2.

The value for maximum total current must not be exceeded.

Note 3.

The listed currents apply when the duty cycle is no greater than 70%. Use the following formula to calculate

the output current when the duty cycle is greater than 70%, where n is the duty cycle.

 Total output current from the listed pins = (IOH × 0.7)/(n × 0.01)

Example when n = 80% and IOH = –10.0 mA

Total output current from the listed pins = (–10.0 × 0.7)/(80 × 0.01)

≅ –8.7 mA

 Total output current from the listed pins = (IOL × 0.7)/(n × 0.01)

Example when n = 80% and IOL = 10.0 mA

Total output current from the listed pins = (10.0 × 0.7)/(80 × 0.01)

≅ 8.7 mA

Note that the duty cycle has no effect on the current that is allowed to flow into a single pin. A current

higher than the absolute maximum rating must not flow into a single pin.

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