UM1620 datasheet(30/41 Pages) STMICROELECTRONICS

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API specification

UM1620

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DocID024388 Rev 3

spaces of main array. The selection of the blocks of the main array is determined by

setting/clearing the corresponding bit in lowEnabledBlocks, midEnabledBlocks or

highEnabledBlocks.

The bit allocations for blocks in one address space are: bit 0 is assigned to block 0, bit 1 to

block 1, etc. The following diagrams show the formats of lowEnabledBlocks,

midEnabledBlocks and highEnabledBlocks for the C90FL module.

For low address space valid bits are from bit 0 to bit (lowBlockNum – 1). In which,

lowBlockNum is the number of low blocks returned from FlashInit();

For middle address space valid bits are from bit 0 and bit (midBlockNum – 1). In which,

midBlockNum is the number of middle blocks returned from FlashInit();

For high address space valid bits are from bit 0 to bit (highBlockNum – 1). In which,

highBlockNum is the number of high blocks returned from FlashInit();

For example, below are bit allocations for blocks in Low/Mid/High Address Space of

SPC564A70:

If no blocks are enabled the C90FL_ERROR_AIC_NO_BLOCK error code is returned.

Depending on the address sequence specified the MISR values are calculated for the

enabled blocks using the corresponding sequence. If the MISR values calculated by the

hardware is not the same as the values passed to this API by the user then the API returns

the error code C90FL_ERROR_AIC_MISMATCH.

Assumptions

It assumes that the Flash block is initialized using a ‘FlashInit()’ API.

Table 45. Bit allocation for blocks in low address space

MSB

LSB

bit 31

…

bit 10

bit 9

bit 8

…

bit 1

bit 0

reserved

…

reserved

block 9

block 8

…

block 1

block 0

Table 46. Bit allocation for blocks in middle address space

MSB

LSB

bit 31

…

bit 4

bit 3

bit 2

bit 1

bit 0

reserved

…

reserved

block 1

block 0

Table 47. Bit Allocation for Blocks in High Address Space

MSB

LSB

bit 31

…

bit 6

bit 5

bit 4

…

bit 1

bit 0

reserved

…

reserved

block 5

block 4

…

Block 1

Block 0

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