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AN2182 bảng dữ liệu(PDF) 7 Page - STMicroelectronics |
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AN2182 bảng dữ liệu(HTML) 7 Page - STMicroelectronics |
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7 / 18 page ![]() AN2182 Low-pass filter 7/18 Figure 3. Ideal low-pass filter impulse response Two issues can be observed at this stage: First, the filter length is infinite. This means that in order to have the ideal low-pass filter, an infinite number of filter coefficients is required. In practice, this cannot be done because of the calculation complexity. To solve this feasibility problem, the filter’s impulse response should be truncated by a known window. In this application note, we will truncate this response using a rectangular window. Truncating the filter’s impulse response, however, changes the ideal rectangular response; more fluctuations are observed in the pass band. In order to reduce this effect, the FIR’s coefficients’ numbers can be increased. Figure 4. Effect of truncating the ideal impulse with a rectangular window In the following sections, we will note: ● W is the window’s time response ● N the number of coefficients included in the window W. This means that the window’s length is (N–1)Ts. The window should be large enough to include at least the first lobe of the sinus cardinal. Second, the truncated response is finite but not causal because there are non-null coefficients on the negative time axis. This means that the filter reacts before being excited by the input signal. Practically, this filter is not feasible. To solve this issue, we will shift the filter’s impulse response by (N–1)Ts/2. By doing so, all coefficients on the negative time axis are 0 and the filter becomes feasible. The impact of shifting the filter’s time response is a phase shift of in the frequency domain. h(k/2Fc) = 0 k>=1 h(0)= 2Fc h(kTs) Fc -Fc 0 1 Frequency Frequency domain Time domain Time W(n) N1 – () π f F s ------ ⋅⋅ |
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