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MC68340 bảng dữ liệu(PDF) 231 Page - Freescale Semiconductor, Inc

tên linh kiện MC68340
Giải thích chi tiết về linh kiện  Integrated Processor with DMA User?셲 Manual
PDF  441 Pages
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nhà sản xuất  FREESCALE [Freescale Semiconductor, Inc]
Trang chủ  http://www.freescale.com
Logo FREESCALE - Freescale Semiconductor, Inc

MC68340 bảng dữ liệu(HTML) 231 Page - Freescale Semiconductor, Inc

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5- 94
MC68340 USER’S MANUAL
MOTOROLA
Because of the stipulation that each instruction must prefetch to replace itself, the concept
of negative tails has been introduced to account for these free clocks on the bus.
On a two-clock bus, it is not necessary to adjust instruction timing to account for the
potential extra prefetch. The cycle times of the microsequencer and bus are matched, and
no additional benefit or penalty is obtained. In the instruction execution time equations, a
zero should be used instead of a negative number.
Negative tails are used to adjust for slower fetches on slower buses. Normally, increasing
the length of prefetch bus cycles directly affects the cycle count and tail values found in
the tables.
In the following equations, negative tail values are used to negate the effects of a slower
bus. The equations are generalized, however, so that they may be used on any speed bus
with any tail value.
NEW_TAIL
= OLD_TAIL + (NEW_CLOCK – 2)
IF ((NEW_CLOCK – 4) >0) THEN
NEW_CYCLE = OLD_CYCLE
+ (NEW_CLOCK -2) + (NEW_CLOCK – 4)
ELSE
NEW_CYCLE = OLD_CYCLE
+ (NEW _CLOCK – 2)
where:
NEW_TAIL/NEW_CYCLE
is the adjusted tail/cycle at the slower speed
OLD_TAIL/OLD_CYCLE
is the value listed in the instruction timing tables
NEW_CLOCK
is the number of clocks per cycle at the slower speed
Note that many instructions listed as having negative tails are change-of-flow instructions
and that the bus speed used in the calculation is that of the new instruction stream.
5.7.2 Instruction Stream Timing Examples
The following programming examples provide a detailed examination of timing effects. In
all examples, the memory access is from external synchronous memory, the bus is idle,
and the instruction pipeline is full at the start.
5.7.2.1 TIMING EXAMPLE 1—EXECUTION OVERLAP. Figure 5-33 illustrates execution
overlap caused by the bus controller's completion of bus cycles while the sequencer is
calculating the next EA. One clock is saved between instructions since that is the
minimum time of the individual head and tail numbers.
Instructions
MOVE.W
A1, (A0)
+
ADDQ.W
#1, (A0)
CLR.W
$30 (A1)
Freescale Semiconductor, Inc.
For More Information On This Product,
Go to: www.freescale.com



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