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SA2005M bảng dữ liệu(PDF) 5 Page - Sames

tên linh kiện SA2005M
Giải thích chi tiết về linh kiện  Evaluation Board for the SA2005M and SA2005P
PDF  12 Pages
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Trang chủ  http://www.sames.co.za
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SA2005M bảng dữ liệu(HTML) 5 Page - Sames

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CIRCUIT DESCRIPTION
ANALOG SECTION
BIAS RESISTOR
The analog (metering) interface described in this section is
designed for measuring 3x
with precision better
than Class 1.
The most important external components for the SA2005M
and SA2005P integrated circuit are the current sense
resistors, the voltage sense resistors and the bias setting
resistor. The resistors used in the metering section should be
of the same type so that temperature effects are minimized.
Pin VREF (SA2005M or P pin 19) is connected to VSS via R7
which determines the on chip bias current. With R7 = 24k
optimum conditions are set. VREF does not require any
additional circuitry.
The voltage drop across the CT termination resistor at rated
current should be at least 16mV. The CT’s used have low
phase shift and a ratio of 1:2500. The CT is terminated with a
3.6
resistor giving a voltage drop across the termination
resistor 86.4mV at rated conditions (Imax for the meter).
Referring to figure 4 the resistors R1 and R2 define the current
levels into the SA2005’s current sense inputs (phase on IIP1
and IIN1). The resistor values are selected for an input current
of 16µA into the current inputs at rated conditions. According
the equation described in the Current Sense inputs section of
the datasheet:
R1=R2=(I / 16µA)xR
/2
=
/ 2500 / 16µA x
/ 2
= 2.7k
I Line current / CT Ratio
The three current channels are identical so R1=R2=R3=R4=
R5=R6.
W
W
W
W
CT TERMINATION RESISTOR
CURRENT SENSOR INPUT RESISTORS
=
SH
230V/60A
60A
3.6
VOLTAGE DIVIDER
Referring to figure 5 the connections for the voltage sense
input for one phase is shown. The current into the A/D
converter (IVP) is set 14µA
at nominal mains voltage. This
voltage sense input saturates at approximately 17µA
. A
nominal voltage current of 14µA allows for 20% over driving.
Each mains voltage is divided down by a voltage divider to 14V.
The current into the voltage sense input is set at 14µA via a
1M
resistor.
The following equation is used to calculate the 14V voltage
drop:
RA = R22 + R23 + R24 + R25
RB = R8 || (R13 + P1)
Combining the two equations gives:
( RA + RB ) / 230V = RB / 14V
A 24k
resistor is chosen for R13 and P1 combined. A 1M
resistor is used for R8.
Substituting the values result in:
RB = 23.44k
RA = RB x ( 230V / 14V - 1 )
RA = 361.6k
Resistor values of R22, R24 are chosen to be 82k
and
resistors R23 and R25 is chosen to be100k
each.
The three voltage channels are identical so
R14 = R16 = R18 = R20 = R22 = R24 = 82k and R15 = R17 =
R19 = R21 = R23 = R25 = 100k
RMS
RMS
W
WW
W
W
W
W
W
Figure 4: Current Input Configuration
R1
2.7k
R2
2.7k
R26
3.6R
CT1
TZ76
GND
I1 In
Neutral
Pin 23
Pin 22
The capacitors C1, C2 and C3 is used to compensate for
phase shifts between the SA2005 voltage sense inputs and
current sense inputs. The on-board Ct’s were characterized
and found to have a constant phase shift of 0.18 degrees. The
value of the phase shift compensation capacitors were
calculated as follows:
C = 1 / (2 x
x Mains frequency x R5 x tan (Phase shift angle))
C = 1 / (2 x
x 50 x 1M
x tan (0.18 degrees))
C = 1.013µF
p
pW
Figure 5: Mains Voltage Divider
R8
1M
R13
22k
V1In
C1
1u
GND
P1
10k
R22
82k
R23
100k
R24
82k
R25
100k
J3
Pin 21
Neutral



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