R5973AD datasheet(29/38 Pages) STMICROELECTRONICS

29 / 38 page

DocID027027 Rev 1

29/38

R5973AD

Application information

However, due to power losses in the passive elements, the real duty cycle is always higher

than this. The real value (that can be measured in the application) should be used in the

following formulas.

The peak current flowing in the embedded switch is:

Equation 34

while its average current is equal to:

Equation 35

This is due to the fact that the current flowing through the internal power switch is delivered

to the output only during the OFF phase.

The switch peak current must be lower than the minimum current limit of the overcurrent

protection (see Table 4 on page 6 for details) while the average current must be lower than

the rated DC current of the device.

As a consequence, the maximum output current is:

Equation 36

where ISW MAX represents the rated current of the device.

The current capability is reduced by the term (1 - D) and so, for example, with a duty cycle of

0.5, and considering an average current through the switch of 1.5 A, the maximum output

current deliverable to the load is 0.75 A.

Figure 18 shows the schematic circuit of this topology for a 12 V output voltage and 5 V

input.

Figure 18. Positive buck-boost regulator

ISW

ILOAD

–

---------------

IRIPPLE

--------------------

ILOAD

–

---------------

VIN



-----------

fSW

---------



ISW

ILOAD

–

---------------

IOUT MAX ISW MAX 1D

–







R5973AD bảng dữ liệu(PDF) 29 Page - STMicroelectronics

R5973AD bảng dữ liệu(HTML) 29 Page - STMicroelectronics

Html Pages

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38

bảng dữ liệu tải về

Link URL