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S1112 bảng dữ liệu(PDF) 9 Page - Seiko Instruments Inc |
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S1112 bảng dữ liệu(HTML) 9 Page - Seiko Instruments Inc |
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9 / 30 page ![]() HIGH RIPPLE-REJECTION AND LOW DROPOUT CMOS VOLTAGE REGULATOR Rev.6.1_00 S-1112/1122 Series Seiko Instruments Inc. 9 Electrical Characteristics Table 7 (Ta = 25 °C unless otherwise specified) Item Symbol Conditions Min. Typ. Max. Unit Test Circuit Output voltage *1 VOUT(E) VIN = VOUT(S) + 1.0 V, IOUT = 30 mA VOUT(S) × 0.99 VOUT(S) VOUT(S) × 1.01 V 1 Output current *2 IOUT VIN ≥ VOUT(S) + 1.0 V 150 *5 ⎯ ⎯ mA 3 Dropout voltage *3 Vdrop IOUT = 100 mA 1.5 V ≤ VOUT(S) ≤ 1.6 V ⎯ 0.32 0.55 V 1 1.7 V ≤ VOUT(S) ≤ 1.8 V ⎯ 0.28 0.47 V 1 1.9 V ≤ VOUT(S) ≤ 2.3 V ⎯ 0.25 0.35 V 1 2.4 V ≤ VOUT(S) ≤ 2.7 V ⎯ 0.20 0.29 V 1 2.8 V ≤ VOUT(S) ≤ 5.5 V ⎯ 0.19 0.26 V 1 Line regulation OUT IN OUT1 V V V • Δ Δ VOUT(S) + 0.5 V ≤ VIN ≤ 6.5 V, IOUT = 30 mA ⎯ 0.05 0.2 %/V 1 Load regulation ΔVOUT2 VIN = VOUT(S) + 1.0 V, 1.0 mA ≤ IOUT ≤ 80 mA ⎯ 12 40 mV 1 Output voltage temperature coefficient *4 OUT OUT V Ta V • Δ Δ VIN = VOUT(S) + 1.0 V, IOUT = 10 mA, −40°C ≤ Ta ≤ 85°C ⎯ ±100 ⎯ ppm/ ° C 1 Current consumption during operation ISS1 VIN = VOUT(S) + 1.0 V, ON/OFF pin = ON, no load ⎯ 50 90 μA2 Current consumption during power-off ISS2 VIN = VOUT(S) + 1.0 V, ON/OFF pin = OFF, no load ⎯ 0.1 1.0 μA2 Input voltage VIN ⎯ 2.0 ⎯ 6.5 V ⎯ ON/OFF pin input voltage “H” VSH VIN = VOUT(S) + 1.0 V, RL = 1.0 kΩ 1.5 ⎯ ⎯ V 4 ON/OFF pin input voltage “L” VSL VIN = VOUT(S) + 1.0 V, RL = 1.0 kΩ ⎯ ⎯ 0.3 V 4 ON/OFF pin input current “H” ISH VIN = 6.5 V, VON/OFF = 6.5 V −0.1 ⎯ 0.1 μA 4 ON/OFF pin input current “L” ISL VIN = 6.5 V, VON/OFF = 0 V −0.1 ⎯ 0.1 μA 4 Ripple rejection RR VIN = VOUT(S) + 1.0 V, f = 1.0 kHz, ΔVrip = 0.5 Vrms, IOUT = 30 mA ⎯ 80 ⎯ dB 5 Short-circuit current Ishort VIN = VOUT(S) + 1.0 V, ON/OFF pin = ON, VOUT = 0 V ⎯ 200 ⎯ mA 3 *1. VOUT(S): Set output voltage VOUT(E): Actual output voltage Output voltage when fixing IOUT(= 30 mA) and inputting VOUT(S) + 1.0 V *2. The output current at which the output voltage becomes 95% of VOUT(E) after gradually increasing the output current. *3. Vdrop = VIN1 − (VOUT3 × 0.98) VOUT3 is the output voltage when VIN = VOUT(S) + 1.0 V and IOUT = 100 mA. VIN1 is the input voltage at which the output voltage becomes 98% of VOUT3 after gradually decreasing the input voltage. *4. A change in the temperature of the output voltage [mV/°C] is calculated using the following equation. ΔVOUT ΔTa [] mV/°C *1 = VOUT(S) [] V *2 × ΔVOUT ΔTa • VOUT [] ppm/°C *3 ÷ 1000 *1. Change in temperature of output voltage *2. Set output voltage *3. Output voltage temperature coefficient *5. The output current can be at least this value. Due to restrictions on the package power dissipation, this value may not be satisfied. Attention should be paid to the power dissipation of the package when the output current is large. This specification is guaranteed by design. |
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