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UM1627 bảng dữ liệu(PDF) 32 Page - STMicroelectronics

tên linh kiện UM1627
Giải thích chi tiết về linh kiện  Standard software driver for C90LC Flash
PDF  38 Pages
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nhà sản xuất  STMICROELECTRONICS [STMicroelectronics]
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UM1627 bảng dữ liệu(HTML) 32 Page - STMicroelectronics

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API specification
UM1627
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DocID024497 Rev 2
Comments
The inputs lowEnabledBlocks, midEnabledBlocks and highEnabledBlocks are bit-mapped
arguments that are used to select the blocks to be evaluated in the Low/Mid/High address
spaces of main array. The selection of the blocks of the main array is determined by
setting/clearing the corresponding bit in lowEnabledBlocks, midEnabledBlocks or
highEnabledBlocks.
The bit allocations for blocks in one address space are: bit 0 is assigned to block 0, bit 1 to
block 1, etc. The following diagrams give an example of the formats of lowEnabledBlocks,
midEnabledBlocks and highEnabledBlocks for the C90LC module.
Refer to Appendix C: Documentation references for the valid bits configuration depending
from the specific microcontroller Flash module sectors.
If no blocks are enabled the C90FL_ERROR_FMR_NO_BLOCK error code is returned.
Table 54. Troubleshooting for FactoryMarginReadCheck()
Returned error bits
Possible causes
Solution
C90FL_ERROR_FMR_
MISMATCH
The MISR value calculated by the
user is incorrect.
Re-calculate the MISR values using
the correct Data and address.
The MISR calculated by the
Hardware is incorrect.
Hardware Error.
C90FL_ERROR_FMR_
NO_BLOCK
None of the Blocks are enabled for
Factory Margin Read Check
Enable any of the blocks using
variables lowEnabledBlocks,
midEnabledBlocks and
highEnabledBlock.
Table 55. Bit allocation for blocks in low address space
MSB
LSB
bit 31
…
bit 10
bit 9
bit 8
…
bit 1
bit 0
reserved
…
reserved
block 9
block 8
…
block 1
block 0
Table 56. Bit allocation for blocks in middle address space
MSB
LSB
bit 31
…
bit 4
bit 3
bit 2
bit 1
bit 0
reserved
…
reserved
reserved
reserved
block 1
block 0
Table 57. Bit allocation for blocks in high address space
MSB
LSB
bit 31
…
bit 6
bit 5
bit 4
…
bit 1
bit 0
reserved
…
reserved
block 5
block 4
…
Block 1
Block 0



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