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HA2556/883 bảng dữ liệu(PDF) 13 Page - Intersil Corporation

tên linh kiện HA2556/883
Giải thích chi tiết về linh kiện  Wideband Four Quadrant Analog Multiplier (Voltage Output)
PDF  20 Pages
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nhà sản xuất  INTERSIL [Intersil Corporation]
Trang chủ  http://www.intersil.com/cda/home
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HA2556/883 bảng dữ liệu(HTML) 13 Page - Intersil Corporation

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DESIGN INFORMATION (Continued)
The information contained in this section has been developed through characterization by Intersil Semiconductor and is for use as
application and design information only. No guarantee is implied.
8-19
HA2556
Let’s first examine the Balance Concept as it applies to the
standard multiplier configuration (Figure 2).
Signals A and B are input to the multiplier and the signal W
is the result. By substituting the signal values into the Bal-
ance equation you get:
And solving for W:
FIGURE 2. MULTIPLIER
Notice that the output (W) enters the equation in the feed-
back to the Z stage. The Balance Equation does not test for
stability, so remember that you must provide negative feed-
back. In the multiplier configuration, the feedback path is
connected to VZ+ input, not VZ-. This is due to the inversion
that takes place at the summing node just prior to the output
amplifier. Feedback is not restricted to the Z stage, other
feedback paths are possible as in the Divider Configuration
shown in Figure 3.
FIGURE 3. DIVIDER
Inserting the signal values A, B and W into the Balance
Equation for the divider configuration yields:
Solving for W yields:
Notice that, in the divider configuration, signal B must remain
≥0 (positive) for the feedback to be negative. If signal B is
negative, then it will be multiplied by the VX- input to produce
positive feedback and the output will swing into the rail.
A
()
B
()
×
5W
()
=
W
AB
×
5
------------
=
HA-2556
1/5V
X
Y
VOUT
Z
VX+
VX-
VY+
VY-
VZ+
VZ-
∑
W
A
B
+
-
+
-
A
+
-
+
-
HA-2556
1/5V
X
Y
VOUT
Z
VX+
VX-
VY+
VY-
VZ+
VZ-
∑
W
A
B
+
-
+
-
+
-
A
+
-
W
–
()
B
()
×
5V
A
–
()
×
=
W
5A
B
-----
=
Signals may be applied to more than one input at a time as
in the Squaring configuration in Figure 4:
Here the Balance equation will appear as:
FIGURE 4. SQUARE
Which simplifies to:
The last basic configuration is the Square Root as shown in
Figure 5. Here feedback is provided to both X and Y inputs.
FIGURE 5. SQUARE ROOT (FOR A > 0)
The Balance equation takes the form:
Which equates to:
Application Circuits
The four basic configurations (Multiply, Divide, Square and
Square Root) as well as variations of these basic circuits
have many uses.
Frequency Doubler
For example, if ACos(
ωτ) is substituted for signal A in the
Square function, then it becomes a Frequency Doubler and
the equation takes the form:
And using some trigonometric identities gives the result:
A
()
A
()
×
5W
()
=
HA-2556
1/5V
X
Y
VOUT
Z
VX+
VX-
VY+
VY-
VZ+
VZ-
∑
W
A
A
+
-
+
-
+
-
+
-
W
A2
5
-----
=
HA-2556
1/5V
X
Y
VOUT
Z
VX+
VX-
VY+
VY-
VZ+
VZ-
W
A
∑
+
-
+
-
A
+
-
+
-
W
()
W
–
()
×
5A
–
()
=
W5A
=
ACos
ωτ
()
()
ACos
ωτ
()
()
×
5W
()
=
W
A2
10
----- 1Cos 2
ωτ
()
+
()
=
Spec Number
511063-883



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