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NX2124 bảng dữ liệu(PDF) 10 Page - Microsemi Corporation

tên linh kiện NX2124
Giải thích chi tiết về linh kiện  300kHz SYNCHRONOUS PWM CONTROLLER
PDF  17 Pages
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nhà sản xuất  MICROSEMI [Microsemi Corporation]
Trang chủ  http://www.microsemi.com
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NX2124 bảng dữ liệu(HTML) 10 Page - Microsemi Corporation

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NX2124/2124A
10
Rev.1.8
02/28/08
Case 2:
F
LC<FESR<FO
40dB/decade
20dB/decade
loop gain
LC
F
ESR
F
compensator
power stage
FZ1 Z2
F
O
F
FP2
P1
F
Figure 5 - Bode plot of Type III compensator
(F
LC<FESR<FO)
If electrolytic capacitors are used as output
capacitors, typical design example of type III
compensator in which the crossover frequency is
selected as F
LC<FESR<FO and FO<=1/10~1/5Fs is shown
as the following steps. Here two SANYO 16MV-WG1500
with 13 m
Ω is chosen as output capacitor.
1. Calculate the location of LC double pole F
LC
and ESR zero F
ESR.
LC
OUT
OUT
1
F
2
LC
1
2
1.5uH 3000uF
2.3kHz
=
×π ××
=
×π ××
=
ESR
OUT
1
F
2
ESRC
1
2
6.5m
3000uF
8.2kHz
=
×π ××
=
×π ×
Ω×
=
2. Set R
2 equal to 10kΩ.
×
Ω×
=
=Ω
2
REF
1
OUT
REF
RV
10k
0.8V
R =
8k
V
-V
1.8V-0.8V
Choose R
1=8.06kΩ.
3. Set zero F
Z2 = FLC and Fp1 =FESR .
4. Calculate C
3 .
3
2
z2
p1
1
11
C =
(-)
2
R
FF
1
11
=
(-)
2
10k
2.3kHz 8.2kHz
=4.76nF
×
×π×
×
×π ×Ω
Choose C
3=4.7nF.
5. Calculate R
3 .
3
P13
1
R
2
FC
1
2
8.2kHz 4.7nF
4.1k
=
×π ××
=
×π ××
=Ω
Choose R
3 =4kΩ.
6. Calculate R
4 with FO=30kHz.
OSC
O
23
4
in
23
V2
F
L
RR
R=
V
ESR
RR
1.5V
2
30kHz 1.5uH 10k
4k
=
5V
6.5m
10k
4k
=37.3k
×π × ××
××
+
×π ×
×
Ω ×Ω
××
Ω +Ω
Choose R
4=37.4kΩ.
7. Calculate C
2 with zero Fz1 at 75% of the LC
double pole by equation (11).
2
Z14
1
C
2
FR
1
2
0.75 2.3kHz 37.4k
2.4nF
=
×π ××
=
×π ×
×
×Ω
=
Choose C
2=2.2nF.
8. Calculate C
1 by equation (14) with pole Fp2 at
half the switching frequency.
1
4
P2
1
C
2
RF
1
2
37.4k
150kHz
28pF
=
×π ××
=
×π ×
Ω×
=
Choose C
1=27pF.



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