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THS0842 bảng dữ liệu(PDF) 19 Page - Texas Instruments

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tên linh kiện THS0842
Giải thích chi tiết về linh kiện  DUAL-INPUT, 8-BIT, 40 MSPS LOW-POWER ANALOG-TO-DIGITAL CONVERTER WITH SINGLE OR DUAL PARALLEL BUS OUTPUT
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THS0842 bảng dữ liệu(HTML) 19 Page - Texas Instruments

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THS0842
DUAL-INPUT, 8-BIT, 40 MSPS LOW-POWER ANALOG-TO-DIGITAL CONVERTER
WITH SINGLE OR DUAL PARALLEL BUS OUTPUT
SLAS246 – DECEMBER 1999
19
POST OFFICE BOX 655303
• DALLAS, TEXAS 75265
PRINCIPLES OF OPERATION
analog input (continued)
To maintain the frequency performance outlined in the specifications, the total source impedance should be
limited to the following equation with fCLK = 80 MHz, CI = 5 pF, RSW = 200 Ω:
R
S t
1
÷ 2f
CLK
C
I
In(256) –R
SW
So, for applications running at a lower fCLK, the total source resistance can increase proportionally.
The analog input of the THS0842 is a differential input that can be configured in various ways depending on
the signal source and the required level of performance. A fully differential connection (Figure 20) will deliver
the best performance from the converter. A dc voltage source, CML, equal to 1.5 V (typical), is made available
to the user to help simplify circuit design when using an ac coupled differential input. This low output impedance
voltage source is not designed to be a reference or to be loaded, but makes an excellent dc bias source and
stays well within the analog input common mode voltage range over temperature. Defining VREFD = VREFT
– VREFB, each single-ended analog input is limited to be between VCML + VREFD/2 and VCML – VREFD/2.
For the ac coupled differential input (Figure 23), full scale is achieved when the +I/Q and –I/Q input signals are
0.5 VPP, with –I/Q being 180 degrees out of phase with +I/Q. The converter will be at positive full scale when
the +I/Q input is at CML + 0.25 V and the –I/Q input is at CML – 0.25 V (+I/Q + I/Q – = 0.5 V). Conversely, the
converter will be at negative full scale when the +I/Q input is equal to CML – 0.25 V and –I/Q is at CML + 0.25 V
(I/Q+ + I/Q– = –0.5 V) (see Figure 19).



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