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LP358 bảng dữ liệu(PDF) 9 Page - Texas Instruments |
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LP358 bảng dữ liệu(HTML) 9 Page - Texas Instruments |
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9 / 22 page ![]() V RF A RI V 1.8 A 3.6 0.5 V VOUT A VIN Vsup+ + VOUT RF VIN RI Vsup- Copyright © 2016, Texas Instruments Incorporated 9 LP358, LP2904 www.ti.com SLOS475A – AUGUST 2005 – REVISED MAY 2017 Product Folder Links: LP358 LP2904 Submit Documentation Feedback Copyright © 2005–2017, Texas Instruments Incorporated 9 Application and Implementation NOTE Information in the following applications sections is not part of the TI component specification, and TI does not warrant its accuracy or completeness. TI’s customers are responsible for determining suitability of components for their purposes. Customers should validate and test their design implementation to confirm system functionality. 9.1 Application Information The LP358 and LP2904 operational amplifiers are useful in a wide range of signal conditioning applications due to the wide VCC range. Inputs can be powered before VCC for flexibility in multiple supply circuits. 9.2 Typical Application A typical application for an operational amplifier in an inverting amplifier. This amplifier takes a positive voltage on the input, and makes the voltage a negative voltage. In the same manner, the amplifier also makes negative voltages positive. Figure 4. Application Schematic 9.2.1 Design Requirements The supply voltage must be selected such that it is larger than the input voltage range and output range. For instance, this application scales a signal of ±0.5 V to ±1.8 V. Setting the supply at ±12 V is sufficient to accommodate this application 9.2.2 Detailed Design Procedure Determine the gain required by the inverting amplifier using Equation 1 and Equation 2. (1) (2) Once the desired gain is determined, select a value for RI or RF. Selecting a value in the kΩ range is desirable because the amplifier circuit uses currents in the milliamp range. This ensures the part does not draw too much current. This example uses 10 kΩ for RI, so 36 kΩ is used for RF; this is determined by Equation 3. (3) |
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