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LPA2164ASOF bảng dữ liệu(PDF) 11 Page - Lowpower Semiconductor inc |
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LPA2164ASOF bảng dữ liệu(HTML) 11 Page - Lowpower Semiconductor inc |
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11 / 15 page ![]() Preliminary Datasheet LPA2164A LPA2164A–00 Version 1.0 May.-2013 Email: marketing@lowpowersemi.com www.lowpowersemi.com Page 11 of 15 into the output drive signal. This noise is from the internal analog reference to the amplifier, which appears as degraded PSRR and THD+N. How to reduce EMI A simple solution is to put an additional capacitor 220pF at power supply terminal for power line. The traces from amplifier to speakers should design as short as we can. Applications Information(for Boost) The LP2164A integrates a 1200KHz fixed frequency, current-mode regulation architecture to regulate the boost convertor output voltage. The LP2164A measures the output voltage through an external resistive voltage divider and compares that to the internal 0.6V reference to generate the error voltage to the inductor current to regulate the output voltage. The use of current-mode regulation improves transient response and control loop stability. When the boost convertor is disabled (EN=Low), both power switches are off. There is no current path from SW to OUT. Therefore, the output voltage discharges to ground. When the boost convertor is enabled (EN=High), a limited start-current charges the output voltage rising to SW, then TH part operates in force PWM mode for regulating the output voltage to the target value. At the beginning of each cycle, the N-channel MOSFET switch is turned on, forcing the inductor current to rise. The current at the source of the switch is internally measured and converted to a voltage by the current sense amplifier. That voltage is compared to the error voltage. When the inductor current rises sufficiently, the PWM comparator turns off the switch, forcing the inductor current to the output capacitor which forces the inductor current to decrease. The peak inductor current is controlled by the error voltage. Thus the output voltage controls the inductor current to satisfy the lode. Setting the Output Voltage Set the output voltage by selecting the resistive voltage divider ratio. The voltage divider drops the output voltage to the 0.6V feedback voltage. Use a 100K resistor for R2 of the voltage divider. Determine the high-side resistor R1 by the equation: Vout=(R1/R2+1) x VFB Vout=(R1/R2+1) x 0.6V |
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