PM2102DPD datasheet(6/16 Pages) SAMES

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PM2102DPD

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PRELIMINARY

SETUP EXAMPLES

The following examples can be used for the setup

conditions indicated.

Example 1

Example 2

Rated voltage:

220V

Rated current:

80A

Sensing element: SHUNT (80A, 50mV, 625µ )

Pulse constant:

800 imp/kWh

Motor constant:

100 imp/kWh

Calculate R6 and R7:

R6 = R7 = (IL / 16µA) x RSH / 2

= 80A / 16µA x 625µ

/ 2.

= 1.5625 k

A standard value of 1K6

is chosen.

The pulse constant is derived from the equation below:

Thus using table 3, we see that R0 = 1, R1 = 1, and R2 = 0.

Rated voltage:

220V

Rated current:

20A

Sensing element: SHUNT (80A, 50mV, 625µ )

Pulse constant:

3200 imp/kWh

Motor constant:

100 imp/kWh

Calculate R6 and R7:

R6 = R7 = (IL / 16µA) x RSH / 2

= 20A / 16µA x 625µ

/ 2.

= 390.625

A standard value of 390

is chosen.

LED p/kWh =

1160 p/sec x 1 / DF_LED) x [3600 /

((Vnom x Imax) / 1000)]

1160 p/sec x 1 / DF_LED) x [3600 /

(220 x 80) / 1000]

800 =

1160 p/sec x (1 / DF_LED ) x 204.54

1 / DF_LED =

0.0033717

DF_LED =

296

MOTOR p/kWh = LED p/kWh / DF_MO

100 = 800 / DF_MO

DF_MO = 8

The pulse constant is derived from the equation below:

MOTOR p/kWh = LED p/kWh / DF_MO

100 = 320 / DF_MO

DF_MO = 32

Thus using table 3, we see that R0 = 1, R1 = 0, and R2 = 0.

Rated voltage:

220V

Rated current:

40A

Sensing element: CT (80A max rated, 1:2500 low phase shift

internal impedance of 50 )

Pulse constant:

1600 imp/kWh

Motor constant:

100 imp/kWh

When a CT is to be used as the sensing element, the

terminating or burden resistor (R16) must also be calculated

and inserted.

R16 is dependent on the type of CT used and can normally be

found on a CT datasheet specified as "burden resistor, Rb".

The terminating or burden resistor for the TZ76V CT is 5.4

yielding 86.4mV at 40A rated.

Calculate R6 and R7:

R6 = R7 = (IL / 2500 / 16µA) x Rterminating / 2

= 40 / 2500 / 16µA x 5.4 / 2

= 2700

CT ratio = 2500

A standard value of 2K7

is chosen.

LED p/kWh =

60p/sec x (1 / DF_LED) x [3600/((Vnom x

Imax)/1000)]

1160 p/sec x (1 / DF_LED) x [3600 / (220 x

20) / 1000]

3200 =

1160 p/sec x (1 / DF_LED ) x 818.18

1 / DF_LED =

0.003371

DF_LED

296

IL= Line current

Example 3

Please note that there should ideally be a voltage drop of

86.4mV but not less than a

minimum of 20mV across the

burden resistor at I

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