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A5974AD bảng dữ liệu(PDF) 36 Page - STMicroelectronics

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Giải thích chi tiết về linh kiện  Zero load current operation
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A5974AD
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Doc ID 018762 Rev 1
8.6
Positive buck-boost regulator
The device can be used to implement a step-up/down converter with a positive output
voltage.
The output voltage is given by:
Equation 33
where the ideal duty cycle D for the buck-boost converter is:
Equation 34
However, due to power losses in the passive elements, the real duty cycle is always higher
than this. The real value (that can be measured in the application) should be used in the
following formulas.
The peak current flowing in the embedded switch is:
Equation 35
while its average current is equal to:
Equation 36
This is due to the fact that the current flowing through the internal power switch is delivered
to the output only during the OFF phase.
The switch peak current must be lower than the minimum current limit of the overcurrent
protection (see Table 4 for details) while the average current must be lower than the rated
DC current of the device.
As a consequence, the maximum output current is:
Equation 37
where ISW MAX represents the rated current of the device.
The current capability is reduced by the term (1-D) and so, for example, with a duty cycle of
0.5, and considering an average current through the switch of 2 A, the maximum output
current deliverable to the load is 1 A.
Figure 25 below shows the circuit schematic of this topology for a 12 V output voltage and
5 V input.
V
OUT
V
IN
D
1D
–
-------------
⋅
=
D
V
OUT
V
IN
V
OUT
+
------------------------------
=
I
SW
I
LOAD
1D
–
---------------
I
RIPPLE
2
--------------------
+
I
LOAD
1D
–
---------------
V
IN
2L
⋅
-----------
D
f
SW
---------
⋅
+
==
I
SW
I
LOAD
1D
–
---------------
=
I
OUT MAX
I
SW MAX
1D
–
()
⋅
≅



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