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LM3524D bảng dữ liệu(PDF) 17 Page - National Semiconductor (TI)

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tên linh kiện LM3524D
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LM3524D bảng dữ liệu(HTML) 17 Page - National Semiconductor (TI)

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Typical Applications (Continued)
THE STEP-UP SWITCHING REGULATOR
Figure 18 shows the basic circuit for a step-up switching
regulator. In this circuit Q1 is used as a switch to alternately
apply V
IN across inductor L1. During the time, tON,Q1isON
and energy is drawn from V
IN and stored in L1; D1 is reverse
biased and I
o is supplied from the charge stored in Co. When
Q1 opens, t
OFF, voltage V1 will rise positively to the point
where D1 turns ON. The output current is now supplied
through L1, D1 to the load and any charge lost from C
o
during t
ON is replenished. Here also, as in the step-down
regulator, the current through L1 has a DC component plus
some
∆I
L.
∆I
L is again selected to be approximately 40% of
I
L. Figure 19 shows the inductor’s current in relation to Q1’s
ON and OFF times.
Since
∆I
L+=
∆I
L−, VINtON =VotOFF −VINtOFF,
and neglecting V
SAT and VD1
The above equation shows the relationship between V
IN,Vo
and duty cycle.
In calculating input current I
IN(DC), which equals the induc-
tor’s DC current, assume first 100% efficiency:
for
η = 100%, P
OUT =PIN
00865023
FIGURE 18. Basic Step-Up Switching Regulator
00865024
FIGURE 19. Relation of Switch Timing to Inductor Current in Step-Up Regulator
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