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OPA129PB bảng dữ liệu(PDF) 7 Page - Texas Instruments |
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OPA129PB bảng dữ liệu(HTML) 7 Page - Texas Instruments |
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7 / 14 page ![]() OPA129 7 SBOS026A www.ti.com CIRCUIT BOARD LAYOUT The OPA129 uses a new pinout for ultra low input bias current. Pin 1 and pin 4 have no internal connection. This allows ample circuit board space for a guard ring surround- ing the op amp input pins—even with the tiny SO-8 surface- mount package. Figure 3 shows suggested circuit board layouts. The guard ring should be connected to pin 8 (sub- strate) as shown. It should be driven by a circuit node equal in potential to the input terminals of the op amp—see Figure 2 for common circuit configurations. TESTING Accurately testing the OPA129 is extremely difficult due to its high performance. Ordinary test equipment may not be able to resolve the amplifier’s extremely low bias current. Inaccurate bias current measurements can be due to: 1. Test socket leakage. 2. Unclean package. 3. Humidity or dew point condensations. 4. Circuit contamination from fingerprints or anti-static treatment chemicals. 5. Test ambient temperature. 6. Load power dissipation. 7. Mechanical stress. 8. Electrostatic and electromagnetic interference. 18 5 4 18 5 4 (A) DIP package (B) SOIC package V– V 0 V+ V– V 0 V+ Connect to proper circuit node, depending on circuit configuration (see Figure 2). Connect to proper circuit node, depending on circuit configuration (see Figure 2). FIGURE 7. Sensitive Photodiode Amplifier. 2 3 6 8 OPA129 Output Pin photodiode HP 5082-4204 5 7 +15V –15V 0.1 µF 5 x 10 9V/W 0.1 µF 10 10 Ω ~1pF to prevent gain peaking Guard Circuit must be well shielded. Out In 2 3 6 8 (C) Inverting Out In 2 3 6 8 (A) Non-Inverting Out In 2 3 6 8 (B) Buffer Guard top and bottom of board. FIGURE 2. Connection of Input Guard. FIGURE 3. Suggested Board Layout for Input Guard. FIGURE 5. High Impedance (1015 Ω) Amplifier. FIGURE 6. Piezoelectric Transducer Charge Amplifier. 1VDC Output 2 3 6 8 Guard 500 Ω 9.5k Ω OPA129 pH Probe R S ≈ 500MΩ 50mV Out 7 5 V– V+ FIGURE 4. Current-to-Voltage Converter. 2 3 6 7 5 8 OPA129 1000M Ω R F Output V O = –IIN • RF V O = –10V/nA 18k Ω 2k Ω Current Input I IN V– V+ V OUT 2 3 6 8 C F OPA129 Low frequency cutoff = 1/(2 πR FCF) = 0.16Hz 10pF 1011 Ω Output V OUT = –∆Q/CF ∆Q R F 7 5 V– V+ |
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