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LTC3404MPMS8 bảng dữ liệu(PDF) 14 Page - Linear Technology

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Giải thích chi tiết về linh kiện  1.4MHz High Efficiency Monolithic Synchronous Step-Down Regulator
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LTC3404
3404fb
Figure 8. Single Lithium-Ion to 2.5V/0.3A Regulator from Design Example
VOUT
2.5V
*
**
***
47pF
10
μF***
CER
6.2
μH*
887k
22
μF**
CER
412k
LTC3404
RUN
ITH
VFB
GND
8
7
6
5
1
2
3
4
PLL LPF
SYNC/MODE
VIN
SW
VIN
2.65V
TO 4.2V
TOKO D63LCB A920CY-6R2M
TAIYO-YUDEN CERAMIC JMK325BJ226MM
TAIYO-YUDEN CERAMIC LMK325BJ106MN
3404 F08a
20pF
TYPICAL APPLICATIO S
VOUT
2.5V
0.6A
CIN***
10
μF
CER
20pF
887k
COUT**
22
μF
CER
*
**
***
47pF
4.7
μH*
LTC3404
RUN
ITH
VFB
GND
8
7
6
5
1
2
3
4
PLL LPF
SYNC/MODE
VIN
SW
VIN
3V TO 4.2V
TOKO D52LC A914BYW-4R7M
TAIYO-YUDEN CERAMIC JMK325BJ226MM
TAIYO-YUDEN CERAMIC LMK325BJ106MN
3404 TA03
412k
Single Li-Ion to 2.5V/0.6A Regulator
Using All Ceramic Capacitors
OUTPUT CURRENT (mA)
95
90
85
80
75
70
0.1
10
100
1000
3404 F8b
1.0
VOUT = 2.5V
L = 6.2
μH
VIN = 3V
VIN = 4.2V
VIN = 3.6V
APPLICATIO S I FOR ATIO
Substituting VOUT = 2.5V, VIN = 4.2V, ΔIL=120mA and
f = 1.4MHz in equation (3) gives:
L
V
MHz
mA
V
V
H
=
−
⎛
⎝⎜
⎞
⎠⎟
= μ
25
1 4
120
1
25
42
6
.
.(
)
.
.
A 6.2
μH inductor works well for this application. For best
efficiency choose a 1A inductor with less than 0.25
Ω
series resistance.
CIN will require an RMS current rating of at least 0.15A at
temperature and COUT will require an ESR of less than
0.25
Ω. In most applications, the requirements for these
capacitors are fairly similar.
For the feedback resistors, choose R1 = 412k. R2 can
then be calculated from equation (2) to be:
R
V
R
k use
OUT
2
08
1
1 875 5
8
=
−
⎛
⎝⎜
⎞
⎠⎟
=
.
.
;
87k
Figure 8 shows the complete circuit along with its effi-
ciency curve.



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