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TPA0142 bảng dữ liệu(PDF) 21 Page - Texas Instruments

tên linh kiện TPA0142
Giải thích chi tiết về linh kiện  2-W STEREO AUDIO POWER AMPLIFIER WITH DC VOLUME CONTROL
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TPA0142 bảng dữ liệu(HTML) 21 Page - Texas Instruments

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TPA0142
2-W STEREO AUDIO POWER AMPLIFIER
WITH DC VOLUME CONTROL
SLOS248B – JUNE 1999 – REVISED MARCH 2000
21
POST OFFICE BOX 655303
• DALLAS, TEXAS 75265
APPLICATION INFORMATION
bridged-tied load versus single-ended mode
Figure 33 shows a Class-AB audio power amplifier (APA) in a BTL configuration. The TPA0142 BTL amplifier
consists of two Class-AB amplifiers driving both ends of the load. There are several potential benefits to this
differential drive configuration but initially consider power to the load. The differential drive to the speaker means
that as one side is slewing up, the other side is slewing down, and vice versa. This in effect doubles the voltage
swing on the load as compared to a ground referenced load. Plugging 2
× VO(PP) into the power equation, where
voltage is squared, yields 4
× the output power from the same supply rail and load impedance (see equation 5).
Power
+
V
(rms)
2
R
L
(5)
V
(rms) +
V
O(PP)
22
RL
2x VO(PP)
VO(PP)
–VO(PP)
VDD
VDD
Figure 33. Bridge-Tied Load Configuration
In a typical computer sound channel operating at 5 V, bridging raises the power into an 8-
Ω speaker from a
singled-ended (SE, ground reference) limit of 250 mW to 1 W. In sound power that is a 6-dB improvement —
which is loudness that can be heard. In addition to increased power there are frequency response concerns.
Consider the single-supply SE configuration shown in Figure 34. A coupling capacitor is required to block the
dc offset voltage from reaching the load. These capacitors can be quite large (approximately 33
µF to 1000 µF)
so they tend to be expensive, heavy, occupy valuable PCB area, and have the additional drawback of limiting
low-frequency performance of the system. This frequency limiting effect is due to the high pass filter network
created with the speaker impedance and the coupling capacitance and is calculated with equation 6.
f
(c) +
1
2
pR
L CC
(6)



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