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R8C2K bảng dữ liệu(PDF) 377 Page - Renesas Technology Corp |
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R8C2K bảng dữ liệu(HTML) 377 Page - Renesas Technology Corp |
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377 / 471 page ![]() R8C/2K Group, R8C/2L Group 19. A/D Converter Rev.1.10 Dec 21, 2007 Page 360 of 450 REJ09B0406-0110 19.6 Output Impedance of Sensor under A/D Conversion To carry out A/D conversion properly, charging the internal capacitor C shown in Figure 19.11 has to be completed within a specified period of time. T (sampling time) as the specified time. Let output impedance of sensor equivalent circuit be R0, internal resistance of microcomputer be R, precision (error) of the A/D converter be X, and the resolution of A/D converter be Y (Y is 1024 in the 10-bit mode, and 256 in the 8-bit mode). VC is generally And when t = T, Hence, Figure 19.11 shows the Analog Input Pin and External Sensor Equivalent Circuit. When the difference between VIN and VC becomes 0.1LSB, we find impedance R0 when voltage between pins VC changes from 0 to VIN-(0.1/ 1024) VIN in time T. (0.1/1024) means that A/D precision drop due to insufficient capacitor charge is held to 0.1LSB at time of A/D conversion in the 10-bit mode. Actual error however is the value of absolute precision added to 0.1LSB. When f(XIN) = 10 MHz, T = 0.25 µs in the A/D conversion mode without sample and hold. Output impedance R0 for sufficiently charging capacitor C within time T is determined as follows. T = 0.25 µs, R = 2.8 kΩ, C = 6.0 pF, X = 0.1, and Y = 1024. Hence, Thus, the allowable output impedance of the sensor equivalent circuit, making the precision (error) 0.1LSB or less, is approximately 1.7 k Ω. maximum. Figure 19.11 Analog Input Pin and External Sensor Equivalent Circuit R0 R (2.8 k Ω) C (6.0 pF) VIN VC MCU Sensor equivalent circuit NOTE: 1. The capacity of the terminal is assumed to be 4.5 pF. R0 T C X Y ---- ln • ------------------- –R – = 1 CR0 R + () -------------------------- –T X Y ---- ln = e 1 CR0 R + () --------------------------T – X Y ---- = VC VIN X Y ---- VIN VIN 1 X Y ---- – = – = VC VIN 1 e 1 CR0 R + () -------------------------- – t – = R0 0.25 10 6 – × 6.0 10 12 – 0.1 1024 ------------ ln • × --------------------------------------------------- – =2.8 3 ×10 – 1.7 3 ×10 ≈ |
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