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RTO20 bảng dữ liệu(PDF) 2 Page - Vishay Siliconix |
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RTO20 bảng dữ liệu(HTML) 2 Page - Vishay Siliconix |
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2 / 4 page ![]() RTO 20 Power Resistors Thick Film Technology Vishay Sfernice Document Number: 50005 For technical questions, contact: sfer@vishay.com www.vishay.com Revision: 05-Jun-07 15 Note: For very low ohmic values, TCR for information CHOICE OF THE HEATSINK The user must choose according to the working conditions of the component (power, room temperature). Maximum working temperature must not exceed 155 °C. The dissipated power is simply calculated by the following ratio: P: expressed in W ΔT: difference between maximum working temperature and room temperature RTH: (j-c): thermal resistance value measured between resistive layer and outer side of the resistor. It is the thermal resistance of the component: (Special Features Table) RTH: (c-a): thermal resistance value measured between outer side of the resistor and room temperature. It is the thermal resistance of the heatsink itself (type, shape) and the quality of the fastening device. Example: RTH: (c-a) for RTO 20 power rating 10 W at ambient temperature + 25 °C Thermal resistance RTH (j-c): 6.5 °C/W Considering equation (1) we have: PERFORMANCE TESTS CONDITIONS TYPICAL DRIFTS Momentary Overload EN 60115-1 2 Pr for R < 2 Ω 1.6 Pr for R ≥ 2 Ω Us < 1.5 UL ± (0.25 % + 0.005 Ω) Rapid Temperature Change EN 60115-1/60068-2-14 5 cycles - 55 °C to + 155 °C ± (0.5 % + 0.005 Ω) Load Life EN 60115-1 1000 h Pr at + 25 °C ± (1 % + 0.005 Ω) Humidity (Steady State) EN 60115-1 56 days R.H. 95 % ± (0.5 % + 0.005 Ω) High Temperature Exposure NF EN 140 000 1000 h - 40 % Pr at + 100 °C ± (0.5 % + 0.005 Ω) Vibration MIL STD 202, Method 204 C Test D ± (0.2 % + 0.005 Ω) Terminal Strength MIL STD 202, Method 211 Test A1 ± (0.2 % + 0.005 Ω) Shock IEC 60115-1 IEC 60068-2-27 Saw tooth: 100 g/6 ms ± (0.5 % + 0.005 Ω) SPECIAL FEATURES Resistance Values ≥ 0.01 ≥ 0.015 ≥ 0.1 ≥ 0.5 Tolerances ± 1 % at ± 10 % Typical Temperature Coefficient Range (- 55 °C/+ 155 °C) ± 900 ppm/°C ± 700 ppm/°C ± 250 ppm/°C ± 150 ppm/°C P = ΔT R TH (j-c) + RTH (c-a) [] ------------------------------------------------------------- 1 () ΔT 155 °C - 25 °C 130 °C == R TH (j-c) + RTH (c-a) = ΔT P ------- = 130 10 ---------- = 13 °C/W R TH (c-a) = 13 °C/W - 6.5 °C/W = 6.5 °C/W |
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