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LM2743MTC/NOPB bảng dữ liệu(PDF) 28 Page - Texas Instruments |
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LM2743MTC/NOPB bảng dữ liệu(HTML) 28 Page - Texas Instruments |
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28 / 44 page ![]() K = 4.8W 4.8W + 0.6W = 89% K = POUT POUT + PTOTAL x 100% PCAP = (1.924A) 2 x 24 m: 1 2 IRMS_RIP = IOUT x D(1 - D) PCAP = (IRMS_RIP) 2 x ESR n 2 28 LM2743 SNVS276I – APRIL 2004 – REVISED FEBRUARY 2019 www.ti.com Product Folder Links: LM2743 Submit Documentation Feedback Copyright © 2004–2019, Texas Instruments Incorporated Typical Applications (continued) PCND2 = (4A) 2 x 13 mΩ x 1.3 x (1 - 0.364) (58) PCND = 98.42 mW + 172 mW = 270.42 mW (59) There are few additional losses that are taken into account: The following equations show IC Operating Loss (PIC). PIC = IQ_VCC x VCC, (60) where IQ-VCC is the typical operating VCC current PIC= 1.5 mA x 3.3V = 4.95 mW (61) The following equations show FET Gate Charging Loss (PGATE). PGATE = n x VCC x QGS x fSW (62) PGATE = 2 x 3.3 V x 3 nC x 300 kHz (63) PGATE = 5.94 mW (64) The value n is the total number of FETs used and QGS is the typical gate-source charge value, which is 3 nC. For the FDS6898A the gate charging loss is 5.94 mW. The following equations show Input Capacitor Loss (PCAP). where (65) (66) Here n is the number of paralleled capacitors, ESR is the equivalent series resistance of each, and PCAP is the dissipation in each. So for example if we use only one input capacitor of 24 m Ω. (67) PCAP = 88.8 mW (68) The following equation shows Output Inductor Loss (PIND). PIND = I 2 OUT x DCR (69) where DCR is the DC resistance. Therefore, for example PIND = (4A) 2 x 11 mΩ (70) PIND = 176 mW (71) The following equations show Total System Efficiency. PTOTAL = PFET + PIC + PGATE + PCAP + PIND (72) (73) (74) |
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