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TS4997 bảng dữ liệu(PDF) 24 Page - STMicroelectronics |
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TS4997 bảng dữ liệu(HTML) 24 Page - STMicroelectronics |
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24 / 34 page ![]() Application information TS4997 24/34 and the maximum value is obtained when: and its value is: Equation 5 Note: This maximum value is only dependent on the power supply voltage and load values. The efficiency is the ratio between the output power and the power supply: Equation 6 The maximum theoretical value is reached when Vpeak = VCC, so: The TS4997 is stereo amplifier so it has two power amplifiers. Each amplifier produces heat due to its power dissipation. Therefore, the maximum die temperature is the sum of each amplifier’s maximum power dissipation. It is calculated as follows: ● Pdiss 1 = Power dissipation of left channel power amplifier ● Pdiss 2 = Power dissipation of right channel power amplifier ● Total Pdiss =Pdiss 1 + Pdiss 2 (W) In most cases, Pdiss 1 = Pdiss 2, giving: The maximum die temperature allowable for the TS4997 is 150°C. In case of overheating, a thermal shutdown protection set to 150°C, puts the TS4997 in standby until the temperature of the die is reduced by about 5°C. To calculate the maximum ambient temperature Tamb allowable, you need to know: ● the power supply voltage value, VCC ● the load resistor value, RL ● the package type, RTHJA Example: VCC=5V, RL=8Ω, RTHJAQFN16=85°C/W (with 2-layer PCB with vias). Using the power dissipation formula given in Equation 5, the maximum dissipated power per channel is: Pdissmax = 633mW And the power dissipated by both channels is: Total Pdissmax = 2 x Pdissmax = 1266mW ∂Pdiss ∂P out --------------------- = 0 ) W ( R Vcc 2 max Pdiss L 2 2 π = η= P out P supply ------------------- = πV peak 4Vcc -------------------- η= π 4 ----- = 78.5% TotalP diss = 2 P diss1 × 42V CC π R L ---------------------- P out 2Pout W () – = |
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