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RT9603CS bảng dữ liệu(PDF) 7 Page - Richtek Technology Corporation |
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RT9603CS bảng dữ liệu(HTML) 7 Page - Richtek Technology Corporation |
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7 / 10 page ![]() RT9603 Preliminary 7 DS9603-00 November 2003 www.richtek.com Before driving the gate of the high side MOSFET up to 12V (or 5V), the low side MOSFET has to be off; and the high side MOSFET is turned off before the low side is turned on. From Figure 1, the body diode "D 2 " had been turned on before high side MOSFETs turned on. Before the low side MOSFET is turned on, the Cgd2 have been charged to VIN. Thus, as Cgd2 reverses its polarity and g2 is charged up to 12V, the required current is gd 2 gd 2 gd2 r2 + == dV V i 12V l C C (4) d tt == g d1 g1 gd1 r1 d V 1 2V l C C (3) d t t (5) (A) 1.428 10 14 12 10 1660 l 9 12 gs1 = × × × = − − (6) (A) 0.88 10 30 12 10 2200 l 9 12 gs2 = × × × = − − It is helpful to calculate these currents in a typical case. Assume a synchronous rectified buck converter, input voltage VIN = 12V, Vg1 = Vg2 = 12V. The high side MOSFET is PHB83N03LT whose Ciss = 1660pF, Crss = 380pF, and tr = 14ns. The low side MOSFET is PHB95N03LT whose Ciss = 2200pF, Crss = 500pF and tr = 30ns, from the equation (1) and (2) we can obtain Figure 2. Two-Phase Synch. Buck Converter Circuit from equation. (3) and (4) the total current required from the gate driving source is By a similar calculation, we can also get the sink current required from the turned off MOSFET. (7) (A) 0.326 10 14 12 10 380 l 9 12 gs1 = × × × = − − (9) 1.745(A) 0.326) (1.428 I I I gd1 gs1 g1 = + = + = (10) 1.28(A) 0.4) (0.88 I I I gd2 gs2 g2 = + = + = Layout Consideration Figure 2 shows the schematic circuit of a two-phase synchronous buck converter to implement the RT9603. The converter operates from 5V to 12V of VIN. When layout the PC board, it should be very careful. The power-circuit section is the most critical one. If not configured properly, it will generate a large amount of EMI. The junction of Q1, Q2, L2 should be very close. Next, the trace from DRVH, and DRVL should also be short to decrease the noise of the driver output signals. SW signals from the junction of the power MOSFET, carrying the large gate drive current pulses, should be as heavy as the gate drive trace. The bypass capacitor C4 should be connected to PGND directly. Furthermore, the bootstrap capacitors (CB) should always be placed as close to the pins of the IC as possible. Select the Bootstrap Capacitor Figure 3 shows part of the bootstrap circuit of RT9603. The VCB (the voltage difference between BST and SW on RT9603) provides a voltage to the gate of the high side power MOSFET. This supply needs to be ensured that the MOSFET can be driven. For this, the capacitance CB has to be selected properly. It is determined by following constraints. (8) 0.4(A) 10 30 12) (12 10 500 I 9 -12 gd2 = × + × × = − BST DRVH SW DRVL VCC IN 14 2 5 7 8 PGND 10 1uF 12V 1uF PHB83N03LT PHB95N03LT 2uH 1uF 1000uF 1.2uH 12V 1500uF 6 L1 C1 L2 C3 Q2 Q1 C2 CB D1 R1 C4 PWM VIN VCORE |
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