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AP72250 bảng dữ liệu(PDF) 21 Page - Diodes Incorporated

tên linh kiện AP72250
Giải thích chi tiết về linh kiện  0.6V TO 5.5V INPUT SYNCHRONOUS BOOST CONVERTER WITH 4.7A SWITCHES
PDF  26 Pages
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nhà sản xuất  DIODES [Diodes Incorporated]
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AP72250 bảng dữ liệu(HTML) 21 Page - Diodes Incorporated

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AP72250
Document number: DS44135 Rev. 1 - 2
21 of 26
www.diodes.com
January 2022
© Diodes Incorporated
AP72250
Application Information (continued)
11
Setting the Output Voltage
The AP72250 has adjustable output voltages starting from 0.8V using an external resistive divider. The resistor values of the feedback network are
selected based on a design trade-off between efficiency and output voltage accuracy. There is less current consumption in the feedback network
for high resistor values, which improves efficiency at light loads. However, values too high cause the device to be more susceptible to noise affecting
its output voltage accuracy. R2 can be determined by the following equation:
������������ =
������. ������ ∙ ������������
������������������������ − ������. ������������
Eq. 3
Table 1 shows a list of recommended component selections for common AP72250 output voltages referencing Figure 1.
Table 1. Recommended Component Selections
AP72250
Output Voltage (V)
R1 (kΩ)
R2
(kΩ)
L (µH)
C1 (µF)
C2 (µF)
1.8
100.0
80.6
0.47
10
2 x 22
2.5
100.0
32.4
0.68
10
2 x 22
3.3
100.0
31.6
1.00
10
2 x 22
5.0
100.0
19.1
1.00
10
2 x 22
5.2
100.0
18.2
1.00
10
2 x 22
12
Inductor
Calculating the inductor value is a critical factor in designing a boost converter. For most designs, the following equation can be used to calculate
the inductor value:
������ =
������������������ ∙ (������������������������ − ������������������)
������������������������ ∙ ∆������������ ∙ ������������������
Eq. 4
Where:
∆IL is the inductor current ripple
fSW is the boost converter switching frequency
For AP72250
, choose ∆IL to be 30% to 50% of the peak inductor current of 4.5A.
The inductor peak current is calculated by:
������������
������������������������ = ������������������������������ ∙ (
������������������������
������������������
) +
∆������������
������
Eq. 5
Peak current determines the required saturation current rating, which influences the size of the inductor. Saturating the inductor decreases the
converter efficiency while increasing the temperatures of the inductor and the internal power MOSFETs. Therefore, choosing an inductor with the
appropriate saturation current rating is important. For most applications, it is recommended to select an inductor of approximately 1.0µH with a DC
current rating of at least 35% higher than the maximum peak current. For hi
ghest efficiency, the inductor’s DC resistance should be less than 50mΩ.
Use a larger inductance for improved efficiency under light load conditions
but beware of the “right-half-plane zero” frequency, F
RHPZ, which is:
������������������������������ =
������������������������
������ ∙ ������ ∙ ������������������������ ∙ ������������������������ ∙ ������
Eq. 6
The right-half-plane zero frequency can cause loop stability so it is ideal to have it be as high as possible. Therefore, for applications using a low
VIN and a high VOUT, the recommendation is to decrease the inductance, the output current, or both, to avoid any possible stability issues caused
by FRHPZ.



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