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ADFS5758 bảng dữ liệu(PDF) 73 Page - Analog Devices |
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ADFS5758 bảng dữ liệu(HTML) 73 Page - Analog Devices |
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73 / 75 page ![]() Data Sheet ADFS5758 Rev. 0 | Page 73 of 75 APPLICATIONS INFORMATION Using the example module shown in Figure 94, the module power dissipation (excluding the power dissipated in the load) can be calculated using the methodology shown in the Power Calculation Methodology (RLOAD = 1 kΩ) section. Assuming a maximum IOUT value of 20 mA and RLOAD value of 1 kΩ, the total module power is calculated as approximately 226 mW. Note that power associated with the external digital isolation is not included in the calculations because this power is dependent on the choice of component used. Replacing the 1 kΩ load with a short circuit, the power dissipation calculation is shown in the Power Calculation Methodology (RLOAD = 0 Ω) section, which shows that the total module power becomes approximately 206 mW in a short-circuit load condition. Power Calculation Methodology (RLOAD = 1 kΩ) Table 55. Quiescent Current Power Calculation Voltage (V) Current (mA) Power (mW) AVDD1 = 24 AIDD1 = 0.05 1.2 AVDD2 = 5 AIDD2 = 2.9 14.5 AVSS = −15 AISS = 0.23 3.45 VLOGIC = 3.3 ILOGIC = 0.01 0.033 Using the voltage and current values in Table 55, the total quiescent current power is 19.18 mW. Next, perform the following calculation: (VDPC+) × (20 mA + IDPC+) = 22.5 V × 20.5 mA = 461.25 mW Assume the dc-to-dc converter is at 90% efficiency. Therefore, VDPC+ power = 512.5 mW. The total input power at the ADFS5758 side of the ADP1031 PMU is therefore 512.5 mW + 19.18 mW = 531.68 mW. Subtracting the 400 mW load power from this value gives the power associated only with the ADFS5758, which is 131.68 mW. Assuming an 85% efficiency ADP1031, the total input power becomes 625.5 mW. Total Module Power = Input Power − Load Power Therefore, 625.5 mW − 400 mW = 225.5 mW Power Calculation Methodology (RLOAD = 0 Ω) Using the voltage and current values in Table 55, the total quiescent current power is 19.18 mW. Next, (VDPC+) × (20 mA + IDPC+) = 4.95 V × 20.5 mA = 101.5 mW Assume the dc-to-dc converter at 65% efficiency. Therefore, VDPC+ power = 156.2 mW. The total input power at the ADFS5758 side of the ADP1031 is therefore 156.2 mW + 19.18 mW = 175.38 mW. Subtracting the 0 mW load power from this value gives the power associated only with the ADFS5758, which is 175.38 mW. Assuming an 85% efficiency ADP1031, the total input power becomes 206.33 mW. Total Module Power = Input Power − Load Power Therefore, 206.33 mW − 0 mW = 206.33 mW |
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