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TC828AECT bảng dữ liệu(PDF) 5 Page - TelCom Semiconductor, Inc

tên linh kiện TC828AECT
Giải thích chi tiết về linh kiện  Switched Capacitor Voltage Converter
PDF  8 Pages
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nhà sản xuất  TELCOM [TelCom Semiconductor, Inc]
Trang chủ  http://www.telcom-semi.com
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TC828AECT bảng dữ liệu(HTML) 5 Page - TelCom Semiconductor, Inc

  TC828AECT Datasheet HTML 1Page - TelCom Semiconductor, Inc TC828AECT Datasheet HTML 2Page - TelCom Semiconductor, Inc TC828AECT Datasheet HTML 3Page - TelCom Semiconductor, Inc TC828AECT Datasheet HTML 4Page - TelCom Semiconductor, Inc TC828AECT Datasheet HTML 5Page - TelCom Semiconductor, Inc TC828AECT Datasheet HTML 6Page - TelCom Semiconductor, Inc TC828AECT Datasheet HTML 7Page - TelCom Semiconductor, Inc TC828AECT Datasheet HTML 8Page - TelCom Semiconductor, Inc  
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5
TC828A
Switched Capacitor
Voltage Converters
TC828A-1 5/1/00
Diode Protection for Heavy Loads
When heavy loads require the OUT pin to sink large
currents being delivered by a positive source, diode protec-
tion may be needed. The OUT pin should not be allowed to
be pulled above ground. This is accomplished by connect-
ing a Schottky diode (1N5817) as shown in Figure 7.
Layout Considerations
As with any switching power supply circuit good layout
practice is recommended. Mount components as close
together as possible to minimize stray inductance and
capacitance. Also use a large ground plane to minimize
noise leakage into other circuitry.
Voltage Doubler/Inverter
Another common application of the TC828A is shown in
Figure 6. This circuit performs two functions in combination.
C1 and C2 form the standard inverter circuit described
above. C3 and C4 plus the two diodes form the voltage
doubler circuit. C1 and C3 are the pump capacitors and C2
and C4 are the reservoir capacitors. Because both sub-
circuits rely on the same switches if either output is loaded,
both will droop toward GND. Make sure that the total current
drawn from both the outputs does not total more
than 40 mA.
Figure 6. Combined Doubler and Inverter
Figure 7. High V– Load Current
C1
D1
D2
D1, D2 = 1N4148
5
4
1
2
3
C2
C4
C3
V
IN
+
V
OUT = VIN
–
V
OUT = (2VIN) –
(V
FD1) – (VFD2)
TC828
TC828
GND
OUT
4
1
Figure 5. Paralleling TC828As to Reduce Output Resistance
C1
C1
5
5
4
3
4
1
2
2
1
3
C2
V
OUT
V
OUT = VIN
R
OUT =
R
OUT
OF SINGLE DEVICE
V
IN
+
NUMBER OF DEVICES
–
TC828
“1”
TC828
“N”
. . .
. . .



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