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OPA835 bảng dữ liệu(PDF) 11 Page - Texas Instruments

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tên linh kiện OPA835
Giải thích chi tiết về linh kiện  50-MHz, 170-關A, Negative-Rail In, Rail-to-Rail Out, Voltage-Feedback Amplifier
PDF  21 Pages
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OPA835 bảng dữ liệu(HTML) 11 Page - Texas Instruments

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+
±
RF
½ OPA2834
Signal and bias to
next stage
2.5 V
GVSIG
2.5 V
VSIG
5 V
RO
VOUT
Signal and bias from
previous stage
RG
C
2.5 V
REF
5 V
R1
RG
+
±
5 V
RF
½ O PA283 4
Sign al and bias to
next sta ge
2.5 V
GVSIG
2.5 V
VSIG
5 V
RO
VOUT
R1
RG
´
Sign al and bias from
previou s stag e
11
OPA2834
www.ti.com
SBOS973 – JUNE 2019
Product Folder Links: OPA2834
Submit Documentation Feedback
Copyright © 2019, Texas Instruments Incorporated
Device Functional Modes (continued)
Figure 9. Noninverting Single Supply With Resistors
Figure 10 shows a typical inverting-amplifier circuit. With a 5-V single-supply, a mid-supply reference generator is
needed to bias the positive side through R1. To cancel the voltage offset that is otherwise caused by the input
bias currents, R1 is selected to be equal to RF in parallel with RG. For example, if a gain of –2 is required and RF
= 3.6 kΩ, select RG = 1.8 kΩ to set the gain and R1 = 1.2 kΩ for bias current cancellation. The value for C is
dependent on the reference, but TI recommends a value of at least 0.1 µF to limit noise into the op amp.
Figure 10. Inverting Single Supply With Reference
Figure 11 illustrates a similar inverting single-supply scenario with the reference generator replaced by the
Thevenin equivalent using resistors and the positive supply. R1 and R2 form a resistor divider from the 5-V supply
and are used to bias the positive side. To cancel the voltage offset that is otherwise caused by the input bias
currents, set the parallel sum of R1 and R2 equal to the parallel sum of RF and RG. C must be added to limit the
coupling of noise into the positive input. For example, if a gain of –2 is required and RF = 3.6 kΩ, select RG =
1.8 kΩ to set the gain. R1 = R2 = 2.4 kΩ for the mid-supply voltage bias and for op-amp input-bias current
cancellation. A good value for C is 0.1 µF. The resistor divider costs less than the 2.5-V reference in Figure 11
but can increase the current from the 5-V supply.



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